How many calories are absorbed by a copper spoon with a mass of 200 grams as it changes from 28°C to 33°C?
A) 0.00027
B) 3
C) 90
D) 13,000
And this one. How do i solve this one?
What did you find?
calories= mass*specifheat*changeintemp
of course,you need the specific heat of copper in calories/gram-C
http://hyperphysics.phy-astr.gsu.edu/hbase/tables/sphtt.html
One of those is correct to one significant digit.
To calculate the calories absorbed by the copper spoon, we can use the formula:
Q = mcΔT
Where:
Q is the heat absorbed (in calories)
m is the mass of the spoon (in grams)
c is the specific heat capacity of copper (in calories/gram°C)
ΔT is the change in temperature (in °C)
First, we need to find the specific heat capacity of copper. The specific heat capacity of copper is approximately 0.386 calories/gram°C.
Using the given values:
m = 200 grams
c = 0.386 calories/gram°C
ΔT = 33°C - 28°C = 5°C
Plugging in these values into the formula, we can calculate the heat absorbed:
Q = (200 grams) x (0.386 calories/gram°C) x (5°C)
= 386 calories/°C x 5°C
= 1930 calories
Therefore, the correct answer is C) 90, which is the closest value to 1930 calories.
To solve for the number of calories absorbed by a copper spoon as it changes in temperature, you can use the specific heat capacity formula:
Q = m * c * ΔT
Where:
Q is the heat energy absorbed by the spoon (in calories)
m is the mass of the spoon (in grams)
c is the specific heat capacity of copper (in calories/gram°C)
ΔT is the change in temperature of the spoon (in °C)
In this case, we are given:
m = 200 grams
ΔT = (33°C - 28°C) = 5°C
We need to find the specific heat capacity of copper (c) to calculate the value of Q.
The specific heat capacity of copper is approximately 0.39 calories/gram°C.
Plugging the given values into the equation:
Q = 200 grams * 0.39 calories/gram°C * 5°C
Calculating the result:
Q = 390 calories
Based on the calculations, the correct answer is C) 90 calories.