How much work must be done to stop a 1250 kg car traveling at 105 km/h?

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  1. Work is Force multiplied by distance.
    Your answer will be in watts.

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  2. So then you have to convert it to joules?

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  3. 131,250

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  4. 531684.027J

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  5. you will first of all conevert km/h to m/s which is 105 multiply 1000 then divide by 3600= 29.7.
    use the formula f= ma.
    1250 multiply by 9.8=12250
    then use formula for work
    w=f multiply by distance
    w=12250 multiply by 29.7=363825J.

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  6. 5.3x〖10〗^5 J

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  7. physics

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  8. -531685J

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  9. First convert km/h to m/s because we need the answer to be J, which is Kg/m^2/s^2
    105km/h=29.2 m/s (the rule is, to go from km/h to m/s is divide by 3.6)
    AND, because the work is being done to slow something down, it is negative.
    So the answer is -531684J. (the comment above me is correct, I just wanted to provide an explanation for anyone who wanted to know how he/she above me got to the correct answer)

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