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A ski starts from rest and slides doen a 22 degree incline 75m long. a) if the coefficient of friction is 0.090, what is the ski's speed at the base of the incline? b). If the snow is level at the foot of the incline and has the same coefficient of friction, how far will the ski travel along the level?
I have part a, i just need b.

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Emily Grossman

  1. energy gained=mg(75/sin22)
    energy lost= mg*mu*cos22*75

    so, final ke=energygained-energy lost

    solve for vf.

    b. mg*mu*distance=finalKE
    solve fordistance.

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    bobpursley

  2. a)20.7m/s
    b)242.9m

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    Pete&Trav

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