College Algebra

Solve 2x(squared)-3x-2=0 using the quadratic formula. Can someone explain this to me please?

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  1. match
    2x^2 - 3x - 2 = 0 with
    ax^2 + bx + c = 0

    so a=2, b=-3, c=-2

    the formula says

    x = (-b ±√(b^2 - 4ac))/(2a)

    substitute the above values and simplify

    (did you get x=2, x=-1/2 ?)

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