How many grams of sodium hydroxide are required to prepare 500 mL of 0.500 M NaOH?

moles NaOH needed = M x L = ??

moles = grams/molar mass
You have moles and molar mass, solve for grams.

whats the answer here?what is the solution?plis

To determine the number of grams of sodium hydroxide (NaOH) required to prepare a 500 mL solution of 0.500 M concentration, we need to follow a series of steps:

Step 1: Calculate the number of moles of NaOH needed.
The molarity (M) of a solution is defined as the number of moles of solute per liter of solution. In this case, we have a 0.500 M NaOH solution and a 500 mL (0.5 L) volume.

Molarity (M) = Moles (mol) / Volume (L)

Rearranging the equation to solve for moles:

Moles (mol) = Molarity (M) x Volume (L)

Therefore, the number of moles of NaOH required is:

Moles (mol) = 0.500 M x 0.5 L

Step 2: Convert moles to grams using the molar mass of NaOH.
The molar mass of NaOH can be found by adding up the atomic masses of the individual elements: Na (sodium) = 22.99 g/mol, O (oxygen) = 16.00 g/mol, H (hydrogen) = 1.01 g/mol.

Molar mass (NaOH) = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 40.00 g/mol

To convert moles to grams, we multiply the number of moles by the molar mass:

Grams (g) = Moles (mol) x Molar mass (g/mol)

Therefore, the number of grams of NaOH required is:

Grams (g) = Moles (mol) x Molar mass (g/mol)

Step 3: Calculate the final answer.
Substitute the calculated number of moles (from Step 1) into the equation from Step 2:

Grams (g) = (0.500 M x 0.5 L) x 40.00 g/mol

Now, calculate:

Grams (g) = 0.250 mol x 40.00 g/mol

Grams (g) = 10.00 g

Hence, 10.00 grams of sodium hydroxide (NaOH) are required to prepare a 500 mL solution of 0.500 M NaOH.