Calculate # of oxygen atoms in 3.15 moles of MgSO4
To calculate the number of oxygen atoms in 3.15 moles of MgSO4, we will first need to determine the number of oxygen atoms present in one mole of MgSO4.
The chemical formula MgSO4 indicates that there is one magnesium (Mg) atom, one sulfur (S) atom, and four oxygen (O) atoms in each molecule of MgSO4.
From the formula, we can see that there are 4 oxygen atoms in one molecule of MgSO4.
Now, we will use Avogadro's number, which is approximately 6.022 x 10^23, to convert moles to atoms.
First, we'll find the number of moles of oxygen in 3.15 moles of MgSO4:
Moles of oxygen = Moles of MgSO4 x (number of oxygen atoms / total number of atoms in MgSO4)
Moles of oxygen = 3.15 mol x (4/1)
Moles of oxygen = 12.6 mol
Next, we'll convert the moles of oxygen to atoms:
Number of oxygen atoms = Moles of oxygen x Avogadro's number
Number of oxygen atoms = 12.6 mol x 6.022 x 10^23
Number of oxygen atoms = 7.5892 x 10^24
Therefore, there are approximately 7.59 x 10^24 oxygen atoms in 3.15 moles of MgSO4.