Can someone help me with this problem

m-2n=16,
4m + n=1

m=2 and n=-7

I solved the second equation for n and got n=-4m+1 then plugged that into the first eqn for n and got m=2. finally i put m into the first eqn and got n=-7
to check, you can see the first eqn: m-2n=16 goes to 2-2(-7)=16 which is correct.

Thank you so much.

no problem. good luck with that class

Of course! I can help you with that problem. To solve this system of equations, we can use either substitution or elimination method. Let's use the elimination method in this case.

First, let's multiply the second equation by 2 to eliminate the variable "n". We get:
8m + 2n = 2

Now, we can add the two equations together:
(m - 2n) + (8m + 2n) = 16 + 2
Combining like terms, we have:
9m = 18

Dividing both sides of the equation by 9, we find:
m = 2

Now, substitute this value of "m" back into either of the original equations. Let's use the first equation:
2 - 2n = 16

Subtracting 2 from both sides, we get:
-2n = 14

Dividing both sides by -2, we find:
n = -7

Therefore, the solution to the system of equations is: m = 2, n = -7.