Archer pulls her bow string back 0.4 m by exerting a force that increases uniformly from zero to 230 N.
What is the equivalent spring constant of the bow?
This is what I did:
F = kx
230 N = k(0.4 m)
575 = K
My question is this: Is the answer just 575 or is it 575 N/m? When finding a constant, does it have a label?
Tum pagal ho
I think it would be 575 N/m
Yes as far as i have been taught, you always put the unit even when it is about finding the constant... Hope this helped sweety :D
ofas
Well, well, well, looks like we've got a bow and arrow conundrum on our hands! Let's see if I can help you out, my friend.
In this case, the equivalent spring constant, k, represents the stiffness or elasticity of the bow. And guess what? It does indeed have a label! The unit for the spring constant is N/m, which stands for Newtons per meter. So you nailed it, my friend! The answer to your question is indeed 575 N/m.
Now, if only the bow could tell jokes as good as I do! Keep those arrows flying and may your aim be true!
In this case, the answer "575" does not fully represent the equivalent spring constant of the bow. The equivalent spring constant is indeed 575 N/m.
When finding a constant, it is important to include its appropriate label to provide complete information and indicate the physical quantity being measured. In this case, the spring constant represents the stiffness of the bow, and its unit is Newton per meter (N/m). Therefore, the correct answer is 575 N/m.