A gas at 65 degrees Celsius occupies 4.22L. At what Celsius temperature will the volume 3.87L, assuming the same pressure?
-kay so ive tried this one like a million times & i cant seem to get the right answer so pls talk me through the steps. like i know the equation is V1/T1=V2/T2 (volume & temp) & all it is is plugging in #s but im not getting the right answer !!! HELP. Like i even converted celsius to Kelvin and that's not workin. cos i have an answer sheet but doesnt shw us how.
so this is what igot
338k x 4.22L/3.87L=368-273
then i get 95 degress celsius.
& the book answer says 37 degres celsius. ): what am i doing wrong !
(V1/T1) = (V2/T2)
(4.22/338) = (3.87/T2)
Cross multiply.
4.22T2 = 338*3.87
T2 = 338*3.87/4.22 = 309.966 K
309.966-273 = 36.966 which rounds to 37.0 to three significant figures. You didn't show all of your work so I don't know if you substituted correctly (or not) or if the trouble is in the algebra. You should know your answer is wrong, however, BECAUSE if the volume goes down the temperature must go down (Charles' Law). You have the temperature going up.
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Yes
Well, it looks like you were almost there, but made a small mistake in your calculations. Let's go through the steps together.
First, convert both temperatures from Celsius to Kelvin. This is because the Kelvin scale starts at absolute zero, which is -273.15 degrees Celsius.
So, for the initial temperature, we have:
T1 = 65 + 273.15 = 338.15 K
Next, we plug in the values into the equation V1/T1 = V2/T2. We want to solve for T2, so we rearrange the equation:
T2 = (V2 * T1) / V1
Now, substitute the values:
T2 = (3.87 L * 338.15 K) / 4.22 L
Simplifying:
T2 = (1309.88605 K) / 4.22 L
T2 ≈ 310.35 K
Finally, convert the temperature back to Celsius:
T2 ≈ 310.35 K - 273.15 = 37.2 degrees Celsius
So, the correct answer is approximately 37 degrees Celsius.
Remember, when performing calculations, it's important to be precise and double-check your steps to avoid any small errors. But hey, at least you were close! Keep up the good work, and don't let those pesky numbers get the better of you!
To solve this problem, you started off correctly by using the equation V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.
First, let's convert the initial temperature of 65 degrees Celsius to Kelvin. To convert Celsius to Kelvin, you need to add 273.15 to the Celsius temperature. So, the initial temperature in Kelvin would be:
T1 = 65 + 273.15 = 338.15 K
Next, let's plug in the given values into the equation:
V1/T1 = V2/T2
(4.22 L) / (338.15 K) = (3.87 L) / T2
Now, let's solve for T2 by cross-multiplying:
4.22 L * T2 = (3.87 L) * 338.15 K
T2 = (3.87 L * 338.15 K) / 4.22 L
T2 ≈ 310.05 K
To convert back to Celsius, subtract 273.15 from the temperature in Kelvin:
T2 ≈ 310.05 K - 273.15 = 36.9 degrees Celsius
So, the final temperature is approximately 36.9 degrees Celsius, which is close to the book answer of 37 degrees Celsius.
It seems you made a mistake when calculating T2. Make sure to multiply the volume and temperature values correctly. Double-check the calculation, and you should get the correct answer.