Find the missing dimension for the three dimensional figure to the nearest tenth, given the volume and other dimensions
L= 8m W=4.6m V=88mcubed
What is the three-dimensional figure?
the equation is LxWxH
so you would do the Volume (88) divided by the other 2.(L&W)
so....
L&W= 8x4.6= 36.8
88/36.8=answer
depth D = V/(L*W) = 88/36.8 = 2.4 m
I have assumed the figure is a rectangular prism.
LxWxH=V
(8)*(4.6)*H= 88
36.8H = 88
H=2.4m
To find the missing dimension of a three-dimensional figure, given the volume and other dimensions, you can use the formula for volume:
Volume = Length × Width × Height
Given that the length (L) is 8m, the width (W) is 4.6m, and the volume (V) is 88m³, we can plug in these values into the formula:
88 = 8 × 4.6 × Height
To find the missing height, divide both sides of the equation by the product of 8 and 4.6:
Height = 88 / (8 × 4.6)
Calculating this expression, we find:
Height ≈ 2.3913 meters
So, the missing dimension (height) of the three-dimensional figure is approximately 2.4 meters (rounded to the nearest tenth).