Given the following sets, select the statement below that is true.
A = {r, i, s, k, e, d}, B = {r, i, s, e}, C = {s, i, r}
(Points : 2)
B �¼ A and B �¼ C
A �¼ C and C �¼ B
B �º A and C �¼ A
C �º A and B �º C
A �º B and C �º B
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Given the following sets, select the statement below that is true.
A = {r, i, s, k, e, d}, B = {r, i, s, e}, C = {s, i, r}
(Points : 2)
B ⊂ A and B ⊂ C
A ⊂ C and C ⊂ B
B ⊆ A and C ⊂ A
C ⊆ A and B ⊆ C
A ⊆ B and C ⊆ B
B ⊂ A means that every element found in B is found in A, but B≠A, i.e. B is a proper subset of A.
If B can equal A, the symbol ⊆ is used.
For example, elements in B are r,i,s and e. Each of the four elements are also found in A which has a higher cardinality than B. So B ⊂ A is true.
On the other hand, the cardinality of B is 4, while that of C is 3. So B⊂C is not possible. So the first statement is false.
You can continue this way, and post your results for checking if you wish.
To determine which statement is true, we need to compare the sets A, B, and C.
Statement B �¼ A and B �¼ C means that set B is not equal to set A and is also not equal to set C.
Let's check if this statement is true:
A = {r, i, s, k, e, d}
B = {r, i, s, e}
C = {s, i, r}
Set B is not equal to set A because set A contains the element 'k' which is not present in set B. Therefore, B �¼ A is true.
Set B is not equal to set C because set C contains the element 's' which is not present in set B. Therefore, B �¼ C is true.
Now that we have confirmed that both B �¼ A and B �¼ C are true, we can conclude that the correct statement is:
B �¼ A and B �¼ C.