Hello,

I don't really know where to begin with this question. Thanks in advance!

Consider the mixing of 10.0 ml of 0.25M K2SO4 with 15.0 ml of 1.10M KCL. What is the concentration of K+, Cl- and SO4^2-?

a) K+___
b) CL-___
c) SO4^2-___

To find the concentration of K+, Cl-, and SO4^2- in the mixture, we need to use the concept of moles and the balanced chemical equation for the dissolution of K2SO4 and KCl.

First, let's calculate the number of moles for both K2SO4 and KCl using the given concentrations and volumes. We can use the equation:

moles = concentration (M) × volume (L)

For K2SO4:
moles of K2SO4 = 0.25M × 0.010L

For KCl:
moles of KCl = 1.10M × 0.015L

To determine the total moles of each ion present in the mixture, we need to use the balanced equation that shows how these salts dissociate in water.

K2SO4 → 2K+ + SO4^2-
KCl → K+ + Cl-

From this equation, we can see that for every mole of K2SO4, we get 2 moles of K+ and 1 mole of SO4^2-, and for every mole of KCl, we get 1 mole of K+ and 1 mole of Cl-.

Hence, the total moles of K+ in the mixture will be:
moles of K+ = 2 × moles of K2SO4 + moles of KCl

Similarly, the total moles of Cl- will be:
moles of Cl- = moles of KCl

And the total moles of SO4^2- will be:
moles of SO4^2- = moles of K2SO4

Finally, to find the concentration of each ion, divide the moles by the total volume of the mixture, which is the sum of the volumes of K2SO4 and KCl.

Concentration = moles / total volume (L)

Now, you can plug in the calculated values to find the concentration of K+, Cl-, and SO4^2-.