x=6/27 = 1/x
whoops x+6/27 = 1/x
Is x+6 the numerator?
Or do you mean x+ (6/27) = 1/x ?
If (x+6)/27 = 1/x, then
x^2 + 6x = 27
x^2 +6x -27 = 0
(x+9)(x-3) = 0
x = -9 or +3.
To find the value of "x" in the equation x = 6/27 = 1/x, we can solve it step by step.
Step 1: Simplify 6/27:
The fraction 6/27 can be simplified by dividing both the numerator and denominator by their greatest common divisor, which is 3. Therefore, we get 6/27 = 2/9.
Step 2: Substitute the simplified value of 6/27 in the equation:
Now, our equation becomes x = 2/9 = 1/x.
Step 3: Solve for "x":
To solve for "x," we need to eliminate the fraction on the right side of the equation. We can do this by multiplying both sides of the equation by "x" to get rid of the denominator. So, (x)(x) = (2/9)(x). This simplifies to x^2 = 2/9x.
Step 4: Multiply both sides of the equation by 9x:
To eliminate the "x" in the denominator, we can multiply both sides of the equation by 9x. This gives us 9x(x^2) = 2.
Step 5: Simplify the equation:
Expanding 9x(x^2) gives us 9x^3 = 2.
Step 6: Divide both sides of the equation by 9:
To isolate the variable, we can divide both sides of the equation by 9 to get x^3 = 2/9.
Step 7: Take the cube root of both sides:
To solve for "x," we need to take the cube root of both sides of the equation. This gives us (cube root of x^3) = (cube root of 2/9).
Step 8: Simplify:
The cube root of x^3 simplifies to x, and the cube root of 2/9 also remains as it is. Therefore, we have x = cube root of (2/9).
Hence, the value of "x" is the cube root of 2/9 (approximately 0.694).