MoP

Sb2(CrO4)5

And Molybdenum (VI) Phosphate

I'm having trouble with these only

Remember that binary compounds (two elements) have the ide ending; e.g., sodium chloride, barium bromide, potassium sulfide, etc. So I would call this one molybdenum phosphide.

The Sb compound is antimony(V) chromate.
The formula for molybdenum(VI) phosphate is Mo(PO4)3.

I can help you with your questions about MoP (Molybdenum (VI) Phosphate) and Sb2(CrO4)5.

Let's start with MoP. Molybdenum (VI) Phosphate is a chemical compound composed of molybdenum in its +6 oxidation state and phosphate ions (PO4) with a 3- charge. To understand MoP better, we need to break down the compound.

Molybdenum (VI) refers to molybdenum in its +6 oxidation state. The Roman numeral VI indicates that molybdenum has lost six electrons, making it positively charged. It means that the molybdenum atom has six valence electrons available for bonding.

Phosphate, on the other hand, is an anion composed of one phosphorus atom and four oxygen atoms. Each oxygen has a -2 charge, resulting in a total charge of -3 for the phosphate ion (PO4). This phosphate ion typically forms compounds with metals by donating its three negative charges.

Now, let's talk about Sb2(CrO4)5. This chemical compound consists of antimony (Sb) in its +5 oxidation state and chromate ions (CrO4) with a 2- charge. To understand the compound, we need to analyze its components.

Antimony (Sb) in its +5 oxidation state means that the antimony atom has lost five electrons, making it positively charged. The Roman numeral V represents the +5 oxidation state.

Chromate (CrO4) is a polyatomic ion composed of one chromium atom and four oxygen atoms. Each oxygen atom in chromate carries a -2 charge, resulting in a total charge of -2 for the ion.

The compound Sb2(CrO4)5 indicates that two antimony ions (Sb) combine with five chromate ions (CrO4). Since the chromate ion carries a 2- charge, it takes two antimony ions with their +5 charge to balance out the negative charge of the five chromate ions.

Now that we have broken down the components of MoP and Sb2(CrO4)5, I hope you have a better understanding of these chemical compounds. If you have any specific questions or want further clarification, feel free to ask.