Find the mass of barium metal (in grams) that must react with O2 to produce enough barium oxide to prepare 1.1 L of a 0.10 M solution of OH^ -.
moles OH^- = 1.1L x 0.1M = ??
moles Ba(OH)2 = 1/2 that.
Convert moles Ba(OH)2 to moles Ba (using the coefficients in the balanced equation)/
Convert moles Ba to grams Ba. g = moles x molar mass.
Well, I'm not exactly a chemist, but I can give it a shot. Instead of mass, let's talk about the weight of the situation, shall we?
To calculate the weight of barium metal, we need to consider the molar ratio between barium metal and barium oxide. Barium oxide has a molar mass of around 153 grams/mol, and it contains one barium atom for every barium oxide molecule.
Next, we need to determine the number of moles of barium oxide required to prepare 1.1 L of a 0.10 M solution of OH^- . Since the OH^- concentration is given in molarity, we're dealing with moles here.
Now, just remember that molarity is the number of moles of solute divided by the volume of the solution in liters. So, if we multiply 0.10 M (moles per liter) by 1.1 L (liters), we get the number of moles of OH^- ions needed.
Finally, because there is a 1:1 ratio between barium oxide and OH^- ions, the number of moles of barium oxide required is equal to the number of moles of OH^- ions.
So, all you need to do now is multiply the number of moles of barium oxide by its molar mass of 153 grams/mol. That should give you the weight of barium metal needed.
I hope I didn't weigh down the explanation too much with my clownish humor!
To find the mass of barium metal required to produce enough barium oxide, we need to determine the number of moles of barium oxide required, and then use the molar mass of barium to calculate the mass.
Step 1: Determine the moles of OH^- in the solution:
The concentration of OH^- is given as 0.10 M, which means we have 0.10 moles of OH^- in 1 liter of solution.
In 1.1 liters, the number of moles of OH^- is:
Moles = concentration × volume
Moles = 0.10 M × 1.1 L
Moles = 0.11 moles OH^-
Step 2: Determine the moles of barium oxide required:
The balanced equation for the reaction of barium metal with oxygen to produce barium oxide is:
2 Ba + O2 -> 2 BaO
From the equation, we can see that 2 moles of barium oxide are produced for every 2 moles of barium metal reacted. Therefore, the number of moles of barium oxide required is equal to the number of moles of barium:
Moles of BaO = Moles of Ba = 0.11 moles OH^-
Step 3: Calculate the mass of barium metal needed:
The molar mass of barium (Ba) is 137.33 g/mol. Therefore, the mass of barium required is:
Mass = Moles × Molar mass
Mass = 0.11 moles × 137.33 g/mol
Mass = 15.11 grams
Therefore, the mass of barium metal required is 15.11 grams.
To find the mass of barium metal that must react with O2, we first need to determine the amount of barium oxide needed to prepare the given solution.
Step 1: Calculate the number of moles of OH^- ions needed
We are given the volume of the solution (1.1 L) and the concentration of OH^- ions (0.10 M). Concentration is expressed as moles per liter, so we can calculate the number of moles using the following equation:
moles = concentration × volume
moles = 0.10 M × 1.1 L
Step 2: Convert moles of OH^- ions to moles of BaO
The balanced chemical equation for the reaction between barium metal (Ba) and oxygen (O2) to produce barium oxide (BaO) is:
2 Ba + O2 → 2 BaO
From the equation, we can see that 2 moles of Ba react with 1 mole of O2 to produce 2 moles of BaO. Therefore, the moles of BaO needed is equal to the moles of OH^- ions.
Step 3: Convert moles of BaO to grams of Ba
To convert moles of BaO to grams of Ba, we need to know the molar mass of BaO. The molar mass of an element or compound is the sum of the atomic masses of its constituent atoms.
The molar mass of Ba is approximately 137.33 g/mol, and the molar mass of O is approximately 16.00 g/mol. Therefore, the molar mass of BaO is:
Molar mass of BaO = molar mass of Ba + molar mass of O = 137.33 g/mol + 16.00 g/mol
Now, we can calculate the mass of Ba using the following equation:
mass = moles × molar mass
mass = moles of BaO × molar mass of Ba
By following these steps, you can find and calculate the mass of barium metal required.