Need help with negation using demorgan law.
~(a and ~b)
I have
~a and b
Is that correct?
To convert the expression ~(a and ~b) using De Morgan's Law, you need to distribute the negation (~) to the individual terms inside the parentheses and change the logical operator.
De Morgan's Law for negation of a conjunction (and) states that ~(A and B) is equivalent to ~A or ~B.
Applying this to ~(a and ~b), we can distribute the negation and change the logical operator:
~(a and ~b) becomes ~a or ~~b
The double negation (~~b) cancels out and simplifies to just b.
Therefore, ~(a and ~b) is equivalent to ~a or b.
So, your answer ~a and b is not correct. The correct answer is ~a or b.