A coin is tossed 3 times. What is the probability of getting 2 heads and 1 tail?

could be

HHT
HTH
THH
each of those has a prob of (1/2)^3 or 1/8

so the prob of your event is 3/8

To find the probability of getting 2 heads and 1 tail when a coin is tossed 3 times, we need to consider the total number of possible outcomes and the number of outcomes that meet our criteria.

1. Total number of outcomes: When a coin is tossed, there are 2 possible outcomes - heads (H) or tails (T). Since the coin is tossed 3 times, the total number of outcomes can be calculated as 2^3 = 8.

2. Number of outcomes with 2 heads and 1 tail: We can calculate the number of outcomes by considering the possibilities for each coin toss. Let's assume H represents a head and T represents a tail. Here are the possible outcomes:
- HHT
- HTH
- THH

So, there are 3 outcomes with 2 heads and 1 tail.

3. Probability: To calculate the probability, we divide the number of favorable outcomes (3) by the total number of possible outcomes (8):
Probability = (Number of favorable outcomes) / (Total number of possible outcomes)
= 3 / 8
= 0.375
= 37.5%

Therefore, the probability of getting 2 heads and 1 tail when a coin is tossed 3 times is 0.375 or 37.5%.