Tim and Sasha have a bag containing 7 red marbles, 3 blue marbles, 6 white marbles, and 4 yellow marbles. Tim reaches in, without looking, pulls out a marble, records the color, and then puts the marble back.Sasha then does the same thing.

What is the probability that Tim and Sasha each drew either a blue marble or a yellow marble?

That would be the product of Tim getting one of those colors, and then Sasha doing the same.

Out of 20 marbles, 7 are blue or yellow.

The answer is therefore (7/20)^2 = 49/400

This is not an algebra question.

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To find the probability that Tim and Sasha each drew either a blue marble or a yellow marble, we need to calculate the probability for each of them individually and then multiply the probabilities together.

First, let's calculate the probability for Tim. The total number of marbles in the bag is 7 (red) + 3 (blue) + 6 (white) + 4 (yellow) = 20 marbles. The probability of Tim drawing a blue or yellow marble out of the 20 marbles is (3 + 4) / 20 = 7 / 20.

Since Tim puts the marble back into the bag, the number of blue and yellow marbles remains the same for Sasha's turn. The total number of marbles is still 20. Therefore, the probability of Sasha drawing a blue or yellow marble out of the 20 marbles is also 7 / 20.

To find the probability that both events occur (Tim and Sasha each drawing either a blue or a yellow marble), we multiply the individual probabilities together: (7/20) * (7/20) = 49 / 400.

Therefore, the probability that Tim and Sasha each drew either a blue or a yellow marble is 49 / 400.