An advertisement is to contain 75 sq.cms of printed area. There is a 2cm margin at the bottom, 3cm margin in each side and no margin at the top. Find the dimensions of the smallest possible poster.

I want the answer

To find the dimensions of the smallest possible poster, we need to subtract the margins from the total printed area.

Given:
- Total printed area = 75 sq.cms
- Margin at the bottom = 2 cm
- Margin on each side = 3 cm

First, let's find the remaining printed area after subtracting the margins.

Total printed area - Bottom margin = Remaining printed area
75 sq.cms - 2 cm = Remaining printed area

To find the dimensions, we need to divide the remaining printed area by the width of the poster. Since there are margins on both sides, we need to subtract the total width of the margins from the width of the poster.

Remaining printed area / (Width of the poster - Total width of margins) = Height of the poster

Let's calculate:

Remaining printed area / (Width of the poster - Total width of margins) = Height of the poster
Remaining printed area / (Width of the poster - (Margin on each side * 2)) = Height of the poster

Now, we can solve for the width of the poster by using the area formula:

Width of the poster = Total printed area / Height of the poster

Let's substitute the values into the formulas and solve for the dimensions.

75 sq.cms - 2 cm = Remaining printed area
Remaining printed area / (Width of the poster - (3 cm * 2)) = Height of the poster
Width of the poster = 75 sq.cms / Height of the poster

Using algebraic steps, we can solve for the dimensions of the smallest possible poster.