Calculate the magnitude of the potential difference between points a and b in the figure if R1=2.36 Ù, R2=4.29 Ù,and R3=10.08 Ù.

There is no figure and you do not explain what Ù means. Are there masses or electric charges at the various points?

To calculate the magnitude of the potential difference between points a and b in the given figure, we need to apply Ohm's Law and use the concept of series and parallel resistors.

First, let's analyze the circuit and identify the resistors connected in series and parallel. From the given information, it is clear that R1 and R2 are connected in series, while R3 is connected in parallel with the combination of R1 and R2.

Step 1: Calculate the equivalent resistance (R12) of resistors R1 and R2, which are connected in series:
R12 = R1 + R2

Substituting the given resistor values:
R12 = 2.36 Ω + 4.29 Ω
R12 = 6.65 Ω

Step 2: Calculate the equivalent resistance (Req) of the combination of R12 and R3, which are connected in parallel:
1/Req = 1/R12 + 1/R3

Substituting the values:
1/Req = 1/6.65 Ω + 1/10.08 Ω

To add the fractions, we need a common denominator:
1/Req = (1*10.08 + 1*6.65)/(6.65*10.08)
1/Req = 16.73 Ω / 67.132 Ω

Taking the reciprocal of both sides:
Req = 67.132 Ω / 16.73 Ω
Req = 4.01 Ω

Step 3: Calculate the potential difference (V) using Ohm's Law:
V = I * Req

Since the current (I) is not given, we need additional information to find it. If the current is given, multiply it by the equivalent resistance (Req) to get the potential difference (V).

Note: If the circuit shown in the figure includes a voltage source or if additional information is provided, it will be necessary to use it to calculate the current (I) and then multiply it by Req to obtain the potential difference (V). Without the current or voltage information, we cannot calculate the potential difference accurately.