These are the points on the graph!
O year = $41000
1 year = $43000
2 year = $46000
3 year = $48500
The following graph shows Bob’s salary from the year 2002 to the year 2005. He was hired in the year 2002; therefore t = 0 represents the year 2002.
List the coordinates of any two points on the graph in (x, y) form.
(___, ___),(___, ___)
b) Find the slope of this line:
Answer:
Show your work here:
c) Find the equation of this line in slope-intercept form.
Answer:
Show or explain your work here:
d) If Bob’s salary trend continued, what would his salary be in the year 2008?
Answer:
Show or explain your work here:
Find the equation of this line in slope-intercept form.
Answer:
Show or explain your work here:
d) If Bob’s salary trend continued, what would his salary be in the year 2008?
Answer:
Show or explain your work here:
Sorry I didn't see the follow-up on your other question.
Slope-intercept form is y = mx + b, where m is slope and b is the y-intercept.
You can easily calculate the slope. It's change in y over change in x. (48500 - 41000)/(3 - 0) = 7500/3 = 2500.
The y-intercept occurs at x=0, so from what you've provided, it is 41,000.
Therefore, we have...
y = 2500x + 41,000
I'm lost
What part are you having trouble with?
Do you understand the equation for slope-intercept form?
Do you understand how to calculate slope?
Do you understand how to find the y-intercept?
No, I don't understand any of it.
The definition for slope-intercept form is y = mx + b. The m is slope, and b is the y-intercept. It's a definition; you just have to memorize it.
For two points (x1, y1) and (x2, y2), the slope is (y2 - y1)/(x2 - x1).
For (4, 2) and (3, -1), the slope is (2 - - 1)/(4 - 3) = (2 + 1) / (4 - 3) = 3 / 1 = 3.
The y-intercept is where the line crosses the graph on the y-axis. The y-axis crosses the x-axis at x=0, so the y-intercept is always at x=0.
If you have any questions, let me know.
a) To find the coordinates of any two points on the graph, we can identify two points and their corresponding values:
Point 1: Year 2002 (t = 0)
Coordinate: (0, $41000)
Point 2: Year 2005 (t = 3)
Coordinate: (3, $48500)
So, the coordinates of the two points on the graph are (0, $41000) and (3, $48500).
b) To find the slope of the line, we can use the formula:
Slope (m) = (y₂ - y₁) / (x₂ - x₁)
Using the coordinates from Point 1 (0, $41000) and Point 2 (3, $48500):
Slope (m) = ($48500 - $41000) / (3 - 0)
= $7500 / 3
= $2500
So, the slope of the line is $2500.
c) To find the equation of the line in slope-intercept form (y = mx + b), we have the slope (m) as $2500.
Using the coordinates from either Point 1 or Point 2 (let's use Point 1: 0, $41000):
Substituting m = $2500, x = 0, y = $41000 into the slope-intercept form:
$41000 = $2500(0) + b
$b = $41000
Therefore, the equation of the line in slope-intercept form is:
y = $2500x + $41000
d) To find Bob's salary in the year 2008, we need to find the value of y when x (t) is 6 (since the difference between 2008 and 2002 is 6 years).
Using the equation of the line we found in part c:
y = $2500x + $41000
Substituting x = 6:
y = $2500(6) + $41000
= $15000 + $41000
= $56000
Therefore, if Bob's salary trend continued, his salary in the year 2008 would be $56000.