can u plz solve ma algebric equation:
3x-4/2=3(x-3)-2
i shall be very thankful to you
If you mean
(3x-4)/2 = 3(x-3) -2
then
3x -4 = 6(x-3) -4
which can be rearranged to
3x -18 +4 -4 = 0, or
3x = 18, so
x = 6
3x-4/2=3(x-3)-2
i shall be very thankful to you
(3x-4)/2 = 3(x-3) -2
then
3x -4 = 6(x-3) -4
which can be rearranged to
3x -18 +4 -4 = 0, or
3x = 18, so
x = 6