h(x)=(2-2x^2)/-2
h(-2)
I get (-2-2(-2)^2)/-2
(-2-2(4)/-2
6/-2=-3
h(-2)=-3
h(x) = (2 - 2x^2)/-2
h(-2) = (2 - 2[2^2])/-2
h(-2) = (2 - 2[4])/-2
h(-2) = (2 - 8)/-2
h(-2) = -6/-2
h(-2) = 3
This is what I get from what the original function was as typed and plugging -2 into it.
I see what I did, I put a neg in front when it should have been and carried it through. Thanks
To find the value of h(-2), you need to substitute -2 for x in the given function h(x)=(2-2x^2)/-2. Here's how you can calculate it step by step:
1. Start with the function h(x) = (2 - 2x^2) / -2.
2. Replace x with -2 in the function: h(-2) = (2 - 2(-2)^2) / -2.
3. Simplify the expression within the parentheses: h(-2) = (2 - 2(4)) / -2.
4. Evaluate the expression inside the parentheses: h(-2) = (2 - 8) / -2.
5. Perform the subtraction operation: h(-2) = (-6) / -2.
6. Perform the division operation: h(-2) = -6 / -2 = 3.
Therefore, h(-2) = 3.
It seems there was an error in your calculations. The correct answer is 3, not -3.