A ship leaves port and heads due east at a rate of 32 miles per hour. Ever since the ship left port, it has been pushed south by a strong constant wind. Five hours after leaving port, the ship is 200 miles away. What is the effective push on the ship from the wind?

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To find the effective push on the ship from the wind, we need to determine the southward component of the ship's velocity.

Since the ship is heading due east, its velocity in the east direction is given as 32 miles per hour. Let's call this V_ship_east.

Let's assume the southward component of the ship's velocity as V_ship_south (which needs to be determined).

To calculate V_ship_south, we can use the information given in the question. It states that five hours after leaving port, the ship is 200 miles away.

We know that the distance traveled by an object is equal to its velocity multiplied by time, so we have the equation:

Distance = Velocity * Time

In this case, the distance traveled by the ship is 200 miles, and the time is 5 hours.

Therefore, we can write the equation as:

200 miles = V_ship_south * 5 hours

Now, solving for V_ship_south, we get:

V_ship_south = 200 miles / 5 hours
= 40 miles per hour

So, the effective push on the ship from the wind is 40 miles per hour.

A ship leaves port and heads due east at a rate of 48 miles per hour. Ever since the ship left port, it has been pushed south by a strong constant wind. Four hours after leaving port, the ship is 240 miles away. What is the effective push on the ship from the wind?

solve it yourself.