How many possible combinations for an 8-digit binary number are there? How did you get this an answer?
Can the numbers be repeated? If not, this is combination of arranging r items out of n items:
nCr = n!/r!(n-r)!
n = 10, r = 8
5! = 5 factorial = 5 * 4 * 3 * 2 * 1 = 120
the johnsons has ben verry bussy and havet done laundry in several weeks the dirty cloth pile hase 540 cloths they figur they can put 27 pices of clothing in a singal load. how many loads of laundry will the johnsens family to do to wash all the itams of clothing
54
To determine the number of possible combinations for an 8-digit binary number, we need to consider that each digit can be either a 0 or a 1. Since we have 8 digits, we can think of it as choosing either 0 or 1 for each digit, independently of the others.
For each digit, there are two options: 0 or 1. Therefore, the total number of combinations is calculated by multiplying these two options together for each digit.
Mathematically, it can be represented as:
Number of combinations = 2^number of digits
In this case, the number of digits is 8, so we substitute the value into the equation:
Number of combinations = 2^8 = 256
Hence, there are 256 possible combinations for an 8-digit binary number.