For x such that 0<x<ƒÎ/2, the expression
�ã(1-cos^2 x)/sinx + �ã(1-sin^2 x)/cosx
is equivalent to:
0, 1, 2, -tanx or sin2x
Any help would be appreciated. Thanks.
I assume the symbol ã is supposed to come out as √ ?
(here is how I get √
while holding down the Alt key, press 251 on the numberpad, then release the Alt key)
√(1-cos^2 x)/sinx + �√(1-sin^2 x)/cosx
√(sin^2x)/sinx + √(cos^2x)/cosx
= sinx/sinx + cosx/cosx
= 1+1
= 2