When varsol and iodine in potassium iodide aqueous solution is mixed, two phases form.

What are the colours in each of the 2 phases when 2ml of I2/KI aqueous solution plus 2 ml of varsol are mixed in a test tube?

What are the colours in each of the 2 phases when each of the following are also added to the test tube containing 2 ml of I2/KI and 2 ml varsol and why:

a) 4 ml varsol

b) 4 ml water

c) 2 drops saturated iodine in KI solution

d) 2 drops saturated sodium thiosulphate

e) 2 drops saturated sodium potassium iodide solution

all i know is that the varsol phase is pink and the I2/KI phase is brown at equilibrium.

Thanks for helping :)

I understand that part, but I don't get in what direction each of the conditions listed above would the equilibrium shift to and how the colour would change.

When varsol and iodine in potassium iodide aqueous solution is mixed, two phases form.

What are the colours in each of the 2 phases when 2ml of I2/KI aqueous solution plus 2 ml of varsol are mixed in a test tube?

What are the colours in each of the 2 phases when each of the following are also added to the test tube containing 2 ml of I2/KI and 2 ml varsol and why:

a) 4 ml varsol

b) 4 ml water

c) 2 drops saturated iodine in KI solution

d) 2 drops saturated sodium thiosulphate

e) 2 drops saturated sodium potassium iodide solution

To determine the colors in each phase when mixing varsol and iodine in potassium iodide aqueous solution, we need to understand the solubility properties and the chemical reactions involved.

Varsol, which is also known as mineral spirits or paint thinner, is a hydrocarbon solvent. It is immiscible with water but can form a solution with organic compounds like iodine.

Potassium iodide (KI) aqueous solution is a polar solvent which can dissolve iodine (I2), forming a brownish-purple solution. Iodine is soluble in polar solvents, but not in nonpolar solvents like varsol.

Now let's go through each scenario and determine the colors in each phase:

a) Adding 4 ml varsol:

Since varsol is immiscible with water, it will form a separate layer in the test tube. The colors will be as follows:
- Top phase (varsol): Transparent or colorless
- Bottom phase (I2/KI solution): Brownish-purple

b) Adding 4 ml water:

Water is a polar solvent, so it will mix with the KI aqueous solution and will not mix with the varsol. The colors will be as follows:
- Top phase (varsol): Transparent or colorless
- Bottom phase (I2/KI/water solution): Brownish-purple

c) Adding 2 drops saturated iodine in KI solution:

Since saturated iodine in KI solution consists of both iodine and potassium iodide, it will dissolve in the aqueous phase. The colors will be as follows:
- Top phase (varsol): Transparent or colorless
- Bottom phase (I2/KI/water/I2/KI solution): Brownish-purple

d) Adding 2 drops saturated sodium thiosulphate:

Sodium thiosulfate reacts with iodine to form sodium iodide and sodium tetrathionate, effectively removing the iodine from the solution. The colors will be as follows:
- Top phase (varsol): Transparent or colorless
- Bottom phase (I2/KI/water/I2/KI/Na2S2O3 solution): Colorless

e) Adding 2 drops saturated sodium potassium iodide solution:

Saturated sodium potassium iodide solution consists of NaI and KI, both of which are soluble in water. Therefore, it will dissolve in the aqueous phase. The colors will be as follows:
- Top phase (varsol): Transparent or colorless
- Bottom phase (I2/KI/water/I2/KI/Na2S2O3/NaI/KI solution): Brownish-purple

Overall, varsol will remain colorless or transparent in all scenarios, while the aqueous phase (I2/KI solution) will be brownish-purple in the absence of any color-altering substances and otherwise depend on the added substances.