How many grams of NiSO4*6H2O are needed to prepare 200*10^2 mL of a 3.5*10^-2 M NiSO4 solution?
How many moles do you need?
moles = M x L = ??
Convert that to grams.
g = ?? moles x molar mass
To calculate the number of grams of NiSO4*6H2O needed, you need to use the molarity (M) and volume (V) of the solution, as well as the molar mass (MM) of NiSO4*6H2O. Here's how you can calculate it step by step:
1. Calculate the number of moles of NiSO4 needed:
- Molarity (M) = moles/volume (L)
- Convert the given volume from mL to L by dividing it by 1000:
Volume (L) = 200 * 10^2 mL / 1000 = 200 L
- Rearrange the formula to solve for moles:
Moles = Molarity * Volume
Moles(NiSO4) = 3.5 * 10^-2 mol/L * 200 L
2. Determine the molar mass of NiSO4*6H2O:
- NiSO4: Nickel (Ni) has a molar mass of 58.69 g/mol, sulfur (S) has a molar mass of 32.07 g/mol, and four oxygen (O) atoms each have a molar mass of 16.00 g/mol.
- H2O: Two hydrogen (H) atoms each have a molar mass of 1.01 g/mol, and one oxygen (O) atom has a molar mass of 16.00 g/mol.
- Multiply the molar masses of each element by their respective subscripts and add everything together:
MM(NiSO4*6H2O) = (58.69 g/mol * 1) + (32.07 g/mol * 1) + (16.00 g/mol * 4) + (2.02 g/mol * 12) + (16.00 g/mol * 6)
3. Calculate the grams of NiSO4*6H2O needed:
- Multiply the moles of NiSO4 obtained in step 1 by the molar mass of NiSO4*6H2O obtained in step 2:
Grams(NiSO4*6H2O) = Moles(NiSO4) * MM(NiSO4*6H2O)
By following these steps, you can calculate the number of grams of NiSO4*6H2O needed to prepare the given solution.