what volume of water must be added to dilute 5.0 L of .50 M HCl solution into a .10 M solution?
To solve this problem, we can use the equation for dilution:
C1V1 = C2V2
where:
C1 = initial concentration of the solution
V1 = initial volume of the solution
C2 = final concentration of the solution
V2 = final volume of the solution
Given information:
C1 = 0.50 M
V1 = 5.0 L
C2 = 0.10 M
We need to find V2, the final volume of the solution.
Rearranging the equation for V2, we have:
V2 = (C1 * V1) / C2
Substituting the values we have:
V2 = (0.50 M * 5.0 L) / 0.10 M
V2 = 25 L
Therefore, you would need to add 25 liters of water to dilute the 5.0 L of 0.50 M HCl solution into a 0.10 M solution.