I would like to know if I did these problem right?

y + 2x =3
Y +2x=-4
Y+2*x-3=0
y=2*x+4=0 If not can you show me the steps

What are you trying to do with these equations?

Please post the exact directions to your problem.

I am also confused since you said "these problem." I am not sure if it's many (these) or one (problem).

My assumption is you have 2 equations:
Y+2x = 3 and
Y+2x = -4

Do you have to take these 2 and find out what x and y equal?

yes

System of equation. substitution or elmination method??

Ok so let me start over. System of equation can be solved by graphing, substitution or elmination method. I only have to choose one method and I was trying the elimination method is that how my problem seems to be?

To determine if you did the problems correctly, let's go through each equation step by step and solve for y.

1. y + 2x = 3:

To solve for y, we need to isolate it on one side of the equation.

y + 2x = 3

Subtract 2x from both sides to move the 2x term to the other side:

y = 3 - 2x

So, the equation is correctly solved for y.

2. Y + 2x = -4:

It seems there might be a typo in your equation. You wrote "Y" instead of "y". Assuming it's a typo, let's solve it:

y + 2x = -4

Subtract 2x from both sides:

y = -4 - 2x

So, the equation is correctly solved for y.

3. Y + 2*x - 3 = 0:

Again, there seems to be a typo. Let's assume it's supposed to be y instead of Y:

y + 2x - 3 = 0

Add 3 to both sides to isolate y:

y = -2x + 3

So, the equation is correctly solved for y.

4. y = 2x + 4 = 0:

In this case, there seems to be extra equals sign (=) in the equation. Let's solve it by assuming it's a typo and remove the second equals sign:

y = 2x + 4

So, the equation is correctly solved for y.

Overall, you solved the equations correctly except for the small typos mentioned.