a teaher chooses a student at random from a class of 10 boys and 15 girls. Find the odds favor of and for the odds against each event.
1. choosing a girl
2. choosing a boy
i don't understand what the odds of something would be
First, find the total amount of students in the class. 10+15=25.
There are 10 girls so the odds of choosing a girl are 10/25, reduced to be 2/5
There are 15 boys so the odds of choosing a boy are 15/25, reduced to be 3/5
The answers are
1. 2/5, or 2 out of 5
2. 3/5, or 3 out of 5
i thought that was probability...... sorry i must have messed up big time on my homework then
It is strange that i am in 7th grade and I know this and you do not....
Choosing a girl at random is more likely to happen because there are 5 more girls than boys.
To calculate the odds of an event, you need to determine the ratio of favorable outcomes to unfavorable outcomes. In this case, the favorable outcomes refer to the event occurring, while the unfavorable outcomes refer to the event not occurring.
Let's calculate the odds for each event:
1. Choosing a girl:
- Favorable outcomes: There are 15 girls in the class.
- Unfavorable outcomes: There are 10 boys in the class.
- Odds in favor: The ratio of favorable to unfavorable outcomes is 15:10, which simplifies to 3:2 odds in favor of choosing a girl.
- Odds against: The ratio of unfavorable to favorable outcomes is 10:15, which simplifies to 2:3 odds against choosing a girl.
2. Choosing a boy:
- Favorable outcomes: There are 10 boys in the class.
- Unfavorable outcomes: There are 15 girls in the class.
- Odds in favor: The ratio of favorable to unfavorable outcomes is 10:15, which simplifies to 2:3 odds in favor of choosing a boy.
- Odds against: The ratio of unfavorable to favorable outcomes is 15:10, which simplifies to 3:2 odds against choosing a boy.
In summary, the odds in favor of choosing a girl are 3:2, while the odds against are 2:3. Conversely, the odds in favor of choosing a boy are 2:3, and the odds against are 3:2.