If you add 4 grams of KCl to 10g of water at 28 C, would the solution be saturated, unsaturated or supersaturated?
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A completely liquid solution of KCl suddenly begins producing solid crystals (as precipitate) when one crystal of KCl is dropped into it. The original solution was
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To determine if the solution would be saturated, unsaturated, or supersaturated, we need to compare the concentration of KCl in the solution with its solubility at the given temperature.
The solubility of KCl in water at 28°C is approximately 34.2 grams per 100 grams of water. If you add 4 grams of KCl to 10 grams of water, the total mass of the solution becomes 14 grams.
To calculate the concentration of KCl in the solution, divide the mass of solute (KCl) by the total mass of the solution, and then multiply by 100 to get a percentage:
(4 grams KCl / 14 grams solution) * 100 = 28.57%
Since the concentration of KCl in the solution (28.57%) is less than its solubility at 28°C (34.2%), the solution would be unsaturated. This means that it can still dissolve more KCl at the given temperature.