Assuming that you have 0.4g of Y(OH)3, calculate the mass of of BaO2 required to react stoichiometrically (1Y:2Ba:3Cu) to produce YBa2Cu3O7.

Now calculate the mass of of CuO required to react stoichiometrically (1Y:2Ba:3Cu) to produce YBa2Cu3O7.

please help!!

.4gY(OH)3> moles Y(OH)3 > moles Y

Then you need twice that number of moles of BaO2 (1Y:2Ba:3Cu),

Take the moles of Y, multiply it by 3 to get the moles of Cu. Knowing the moles of Cu, you know the moles of CuO, convert that to grams.
I will be happy to critique your work.

17

To calculate the mass of BaO2 required, we will follow these steps:

Step 1: Convert the given mass of Y(OH)3 to moles.
The molar mass of Y(OH)3 = (1 x molar mass of Y) + (3 x molar mass of O) + (3 x molar mass of H)
Let's assume the molar mass of Y = M₁ grams/mol

Given mass of Y(OH)3 = 0.4g
Moles of Y(OH)3 = (0.4g) / (molar mass of Y(OH)3)

Step 2: Calculate the moles of Y.
As per the balanced chemical equation, 1 mole of Y(OH)3 reacts with 1 mole of Y.
Moles of Y = Moles of Y(OH)3

Step 3: Calculate the moles of BaO2.
As per the balanced chemical equation, 1 mole of Y reacts with 2 moles of BaO2.
Moles of BaO2 = 2 x Moles of Y

Step 4: Calculate the mass of BaO2.
Mass of BaO2 = Moles of BaO2 x Molar mass of BaO2

To calculate the mass of CuO required, we will follow a similar approach:

Step 1: Calculate the moles of Cu.
As per the balanced chemical equation, 1 mole of Y reacts with 3 moles of Cu.
Moles of Cu = 3 x Moles of Y

Step 2: Calculate the moles of CuO.
As per the balanced chemical equation, 1 mole of Cu reacts with 1 mole of CuO.
Moles of CuO = Moles of Cu

Step 3: Calculate the mass of CuO.
Mass of CuO = Moles of CuO x Molar mass of CuO

I hope this step-by-step explanation helps you with your calculations. Let me know if you have any further questions!

To find the mass of BaO2 required, we need to follow these steps:

1. Convert the mass of Y(OH)3 to moles. To do this, we divide the given mass by the molar mass of Y(OH)3.

The molar mass of Y(OH)3 can be calculated by adding the atomic masses of yttrium (Y), oxygen (O), and hydrogen (H).

Next, we find the atomic masses from the periodic table:

Y = 88.91 g/mol
O = 16.00 g/mol
H = 1.01 g/mol

Thus, the molar mass of Y(OH)3 is:
Molar mass = (1 * Y) + (3 * O) + (3 * H) = (1 * 88.91) + (3 * 16.00) + (3 * 1.01) = 123.94 g/mol

Now we can calculate the number of moles:
Moles of Y(OH)3 = mass of Y(OH)3 / molar mass of Y(OH)3 = 0.4g / 123.94 g/mol

Let me know the result of your calculation, and I'll proceed to the next step.