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7. At pH 7.4 a weak organic acid with a pKa of 6.4 would be ionized at what percent?
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7. At pH 7.4 a weak organic acid with a pKa of 6.4 would be what percent ionized.
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I worked this below. If not for you let me know and I'll try to find it and post a link.
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7. At pH 7.4 a weak organic acid with a pKa of 6.4 would be ionized at what percent?
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To determine the percent ionization of a weak acid at a certain pH, you need to consider the acid
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7. At pH 7.4 a weak organic acid with a pKa of 6.4 would be ionized at what percent?
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Fifth or sixth post. See your others.
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7. At pH 7.4 a weak organic acid with a pKa of 6.4 would be ionized at what percent?
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%ionization =[(H^+)/(acid)]*100 = ?? We have the (H^+), or we can get it, from pH. I find 3.98 x
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7. At pH 7.4 a weak organic acid with a pKa of 6.4 would be 60% ionized
% Ionization =[(H^+)/(acid)]*100 = 3.98 x 10^-8 HA ==>
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I don't get 60%. Is that your answer? An answer from your notes?
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0.1M x 0.15 ionized = 0.015 concn. ...........HX --> H^+ +X^- initial...0.1.....0.....0
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