The perimeter of a triangle is 102. side b is twice as long as side A. and side C is three less than side B.. how long is each side.

B = 2A

C = B - 3 = 2A-3

A + 2A + 2A - 3 =102

Solve for A, then B and C.

sharkiesha NO!!

-15+3/7x-6

5. The second side of a triangle is twice as long as the first side. The third side is 8 inches

longer than the first side. The perimeter is 28 inches. Find the length of the longest side.

To find the lengths of the sides of the triangle, we can use the given information about their relationships and the perimeter of the triangle. Let's break down the problem step by step.

1. Let's assign variables to the three sides of the triangle: A, B, and C.
2. From the given information, we know that side B is twice as long as side A. So we can represent this as B = 2A.
3. Similarly, it is mentioned that side C is three less than side B. Therefore, C = B - 3.
4. The perimeter of a triangle is the sum of the lengths of all its sides. In this case, the perimeter is given as 102. Hence, A + B + C = 102.
5. We can substitute the values of B and C from steps 2 and 3 into the equation from step 4 to form a single equation in terms of A: A + 2A + (2A - 3) = 102.
6. Simplifying the equation: 5A - 3 = 102.
7. Add 3 to both sides of the equation: 5A = 105.
8. Divide both sides of the equation by 5: A = 21.
9. Now that we have the value of A, we can substitute it back into the equations from step 2 and 3 to solve for B and C.
- B = 2A = 2 * 21 = 42.
- C = B - 3 = 42 - 3 = 39.

Therefore, the lengths of the sides of the triangle are:
Side A = 21 units,
Side B = 42 units,
Side C = 39 units.