A bag contains a mixture of copper and lead BB's. The average density of the BB's is 9.87 g/cm^3. Assuming that copper and lead are pure, determine the relative amounts of each kind of BB.
Density Pb = 11.4
Density Cu = 8.96
You need to confirm these.
Let x = fraction Pb BBs, then
1-x = fraction Cu BBs.
11.4(x) + 8.96(1-x) = 9.87
Solve for x, then evaluate 1-x.
check my work. Check my thinking.
What do you do next?
Solve for x. After you know x, you can find 1-x. x is lead and 1-x is Cu.
Nice website for me!!! Ok and good!
LED text displays refer to types that are specialized and limited to display of alpha-numeric characters. Most types display either one character or a group of characters
To determine the relative amounts of copper and lead BB's in the bag, we need to use the concept of density.
We know that the average density of the mixture is 9.87 g/cm^3. Since copper and lead are pure elements, we can look up their individual densities. The density of copper is 8.96 g/cm^3, while the density of lead is 11.34 g/cm^3.
Let's assume that the bag contains x grams of copper BB's and y grams of lead BB's. The total volume of the BB's can be calculated using the average density:
(x + y) / V = 9.87 g/cm^3
where V represents the total volume of the BB's.
Now, we can express the mass of each type of BB in terms of their volume and density:
Mass of copper BB's = x / (8.96 g/cm^3)
Mass of lead BB's = y / (11.34 g/cm^3)
Since the total mass of the BB's is the sum of the mass of copper BB's and the mass of lead BB's:
x + y = m
where m represents the total mass of the BB's.
Now, we have two equations:
x + y = m
(x / 8.96) + (y / 11.34) = V
We can solve these equations simultaneously to find the relative amounts of copper and lead BB's.