When some volcanoes erupt, big rocks have been measured to shoot upward with speeds of about 1000 m/s. Show that, neglecting air resistance, these rocks reach heights exceeding 50km.

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To show that the rocks reach heights exceeding 50 km, we need to use the principles of projectile motion. In this case, we will assume that air resistance can be neglected, which makes the analysis simpler.

We can start by using the equations of motion to determine the time the rock takes to reach its maximum height.

The initial velocity of the rock, Vi, is 1000 m/s, and the final velocity at the maximum height, Vf, is 0 m/s since the rock momentarily comes to rest at the peak of its trajectory.

Using the equation Vf = Vi + at, where a is the acceleration due to gravity (-9.8 m/s²), we can solve for the time taken to reach the maximum height:

0 = 1000 m/s + (-9.8 m/s²)t

Simplifying the equation:

9.8t = 1000

t = 1000 / 9.8

t ≈ 102.04 seconds

Next, we can use the equation for the height (h) reached by the rock:

h = Vi * t + (1/2) * a * t²

Substituting the values:

h = 1000 m/s * 102.04 s + (1/2) * (-9.8 m/s²) * (102.04 s)²

Simplifying the equation:

h = 102,040 m + (1/2) * (-9.8 m/s²) * 10,412.16 s²

h = 102,040 m - 50,818 m

h ≈ 51,222 m

So, neglecting air resistance, the rock reaches a height of approximately 51,222 meters or 51.2 km.

Therefore, it can be concluded that these rocks reach heights exceeding 50 km when they erupt from volcanoes without considering the effects of air resistance.