A car traveling along a level road uniformly increases its speed from rest to 28m/s in 8.0s. Show that it travels a distance of 112m in this time.
vf^2=vi^2+2ad solve for d
Are you memorizing these formulas? Flash cards can do that. Memorize them.
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To find the distance traveled by the car, we can use the formula:
distance = initial velocity * time + (1/2) * acceleration * time^2
Given:
initial velocity (u) = 0 m/s (car starts from rest)
final velocity (v) = 28 m/s
time (t) = 8.0 s
We need to find the distance (s) traveled by the car in this time.
First, let's find the acceleration using the formula:
acceleration (a) = (final velocity - initial velocity) / time
Substituting the given values, we have:
acceleration (a) = (28 m/s - 0 m/s) / 8.0 s
= 28 m/s / 8.0 s
= 3.5 m/s^2
Now, we can substitute the values of initial velocity, time, and acceleration into the distance formula:
distance (s) = (0 m/s) * (8.0 s) + (1/2) * (3.5 m/s^2) * (8.0 s)^2
= 0 m/s + (1/2) * 3.5 m/s^2 * 64 s^2
= 0 m + 1.75 m/s^2 * 64 s^2
= 112 m
Therefore, the car travels a distance of 112 m in 8.0 seconds.