Helium gas in a balloon occupies 2.5 L at 300.0 K. The balloon is dipped into liquid nitrogen that is at a temperature of 80.0 k. What will the volume of the helium in the balloon at the lower temperature be?

I got a weird answer like .66667 and i used charles law

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  1. assuming pressure would be the same (it is not if one is submerged in a liquid).


    V2=2.5*80/(300)=2.5*4/15 which is about in my head 1/4*2.5 which is your answer

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  2. thanku!

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  3. This is not a answer choice for my test. It seems that may be wrong.

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