If the column of water in the water barometer fore to a height of 35ft, what would the atmospheric pressure be in mm Hg?
mmH20X(density of water/density of Hg)=
mmHg Density of water=0.99707 Density Hg=13.5340
To find the atmospheric pressure in mm Hg, we can use the formula:
mmHg = mmH2O * (density of water / density of Hg)
Given:
mmH2O = 35 ft
Density of water = 0.99707 g/cm^3
Density of Hg = 13.5340 g/cm^3
First, let's convert the height from feet to mm H2O:
1 ft = 304.8 mm
35 ft = 35 * 304.8 mm = 10,668 mm H2O
Next, we can substitute the values into the formula:
mmHg = 10,668 mm H2O * (0.99707 g/cm^3 / 13.5340 g/cm^3)
Calculating the result:
mmHg ≈ 787.44
Therefore, the atmospheric pressure would be approximately 787.44 mm Hg when the column of water in the water barometer reaches a height of 35 ft.
To calculate the atmospheric pressure in mm Hg, we need to multiply the height of the water column in feet by a conversion factor. Here's how you can do it step by step:
1. Convert the height of the water column from feet to millimeters (mm). To do this, multiply the height in feet by 304.8 since 1 foot is equal to 304.8 mm. In this case, the height is 35 ft, so the calculation is: 35 ft * 304.8 mm/ft = 10668 mm.
2. Determine the conversion factor from mm H2O (millimeters of water) to mm Hg (millimeters of mercury). The conversion factor is the ratio of the densities of water (in mm H2O) and mercury (in mm Hg). In this case, the density of water is 0.99707 mm H2O and the density of mercury is 13.5340 mm Hg.
3. Use the conversion factor to find the atmospheric pressure in mm Hg. Multiply the height of the water column in mm (10668 mm) by the conversion factor (0.99707 mm H2O/13.5340 mm Hg): 10668 mm * (0.99707 mm H2O/13.5340 mm Hg) ≈ 784.59 mm Hg.
Therefore, if the column of water in the water barometer rose to a height of 35 ft, the atmospheric pressure would be approximately 784.59 mm Hg.