What is the percent by volume of isopropyl alcohol in a solution that contains 24 mL of isopropyl alcohol in 1.1 L of water?
this the other one i need help with and thanks for the last help
what is the percent by volume of isopropyl alcohol in a solution that contains 24 ml of isopropyl alcohol in 1.1 L of water
To find the percent by volume of isopropyl alcohol in the solution, we need to compare the volume of isopropyl alcohol to the total volume of the solution.
First, convert the volume of isopropyl alcohol from milliliters (mL) to liters (L). Since 1 L = 1000 mL, divide 24 mL by 1000 to get 0.024 L.
Next, add the volume of isopropyl alcohol to the volume of water to find the total volume of the solution. In this case, it would be 0.024 L + 1.1 L = 1.124 L.
To find the percent by volume of isopropyl alcohol, divide the volume of isopropyl alcohol by the total volume of the solution, and then multiply by 100. In this case, (0.024 L / 1.124 L) x 100 = 2.14%.
Therefore, the percent by volume of isopropyl alcohol in the solution is approximately 2.14%.
I have answer
%$ by volume means (mL solute/100 mL solution)*100
Assuming the volume of isopropyl alcohol and water are additive, then
(24/(1,100 + 24)*100 =