A pound of body fat stores an amount of chemical energy equivalent to 3500 Cal. When sleeping, the average adult burns or expends about 0.45 Cal/h for every pound of body weight. How many Calories would a 126 lb person burn during 7 hours of sleep? (Note that 1 Cal = 1 kcal.)
To find out how many Calories a 126 lb person would burn during 7 hours of sleep, we need to calculate the total calorie expenditure by multiplying the calorie burn rate (0.45 Cal/h) by the number of hours slept (7 hours) and the weight (126 lb).
Here's how you can calculate it step by step:
1. Convert the body weight from pounds to kilograms.
- 1 lb = 0.453592 kg
- 126 lb * 0.453592 kg/lb ≈ 57.153312 kg (rounded to 6 decimal places)
2. Calculate the total calorie expenditure during sleep.
- Calorie burn rate per hour = 0.45 Cal/h
- Number of hours slept = 7 hours
- Total calories burned = calorie burn rate per hour * number of hours * body weight
- Total calories burned = 0.45 Cal/h * 7 hours * 57.153312 kg
Now, let's do the calculation:
Total calories burned ≈ 220.050768 Cal (rounded to 6 decimal places)
Therefore, a 126 lb person would burn approximately 220.051 Calories during 7 hours of sleep.
To calculate the number of calories a person would burn during 7 hours of sleep, we'll multiply the number of calories burned per hour by the number of hours slept.
1 pound of body weight burns 0.45 Cal/hour
So for a 126 lb person:
0.45 Cal/hour * 126 lb = 56.7 Cal/hour
Now we'll multiply this by the number of hours slept:
56.7 Cal/hour * 7 hours = 396.9 Calories
Therefore, a 126 lb person would burn approximately 396.9 Calories during 7 hours of sleep.