What is the percent by mass of 3.55 g NaCl dissolved in 88 g H2O?
2. A solution is made by adding 1.23 moles of KCl to 1000.0 g of water. What is the % by mass of KCl in this solution?
3. If you have 100.0 mL of a 25% aqueous solution of ethanol, what volumes of ethanol and water are in the solution?
4. What is the percent by volume of isopropyl alcohol in a solution that contains 24 mL of isopropyl alcohol in 1.1 L of water?
5. What is the Molarity of an aqueous solution containing 160.0 g of ammonium nitrate (NH4NO3) in 2500 m L of solution?
6. What is the Molarity of a bleach solution containing 11.7 g of NaOCl per liter of bleach?
7. Calculate the Molarity of 2.30 L of a solution containing 2.45 g of dissolved KBr.
8. How many moles of solute are contained in 15.25 mL of 2.10 M CaCl2?
9. How many grams of KOH are in 64.3 mL of a 0.0238M KOH solution?
10. What volume of a 3.00M KI stock solution would you use to make 0.300 L of a 1.25M KI solution?
can you please help me
how do you calculate the % by mass of 3.55g of NaCl in 88g of water?
what is the percent by volume of isopropyl alcohol in a solution that contains 24 mL of isopropyl alcohol in 1.1L of water
Of course! I'd be happy to help you with these questions. Let's go through each question step by step.
1. To find the percent by mass of NaCl in the solution, you need to divide the mass of NaCl by the total mass of the solution (NaCl + H2O) and multiply by 100. In this case, the mass of NaCl is given as 3.55 g, and the mass of H2O is given as 88 g. So the percent by mass of NaCl is (3.55 g / (3.55 g + 88 g)) * 100.
2. For the percent by mass of KCl in the solution, divide the mass of KCl by the total mass of the solution (KCl + water) and multiply by 100. In this case, the number of moles of KCl is given as 1.23 moles, and the mass of water is given as 1000.0 g. To find the mass of KCl, multiply the number of moles by its molar mass. Then, calculate the total mass of the solution by adding the mass of KCl with the mass of water. Finally, calculate the percent by mass by dividing the mass of KCl by the total mass of the solution and multiply by 100.
3. To determine the volumes of ethanol and water in the solution, you need to know the total volume and the percent by volume of ethanol. In this case, the total volume is given as 100.0 mL, and the solution is described as a 25% aqueous solution of ethanol. To find the volume of ethanol, multiply the total volume by the percent by volume of ethanol. Similarly, to find the volume of water, subtract the volume of ethanol from the total volume.
4. The percent by volume of isopropyl alcohol in the solution is calculated by dividing the volume of isopropyl alcohol by the total volume of the solution and multiplying by 100. In this case, the volume of isopropyl alcohol is given as 24 mL, and the total volume of the solution is given as 1.1 L. So the percent by volume of isopropyl alcohol is (24 mL / (24 mL + 1.1 L)) * 100.
5. To find the molarity of the solution, you need to divide the number of moles of solute by the volume of the solution in liters. In this case, the mass of ammonium nitrate is given as 160.0 g, and the volume of the solution is given as 2500 mL. To find the number of moles of ammonium nitrate, divide its mass by its molar mass. Then, convert the volume of the solution from mL to L by dividing by 1000. Finally, calculate the molarity by dividing the number of moles by the volume in liters.
6. The molarity of the bleach solution can be found by dividing the number of moles of NaOCl by the volume of the solution in liters. In this case, the mass of NaOCl is given as 11.7 g, and the volume of the bleach is given as 1 L. To find the number of moles of NaOCl, divide its mass by its molar mass. Finally, divide the number of moles by the volume in liters to find the molarity.
7. In order to calculate the molarity of the solution, you first need to find the number of moles of KBr. This can be calculated by dividing the mass of KBr by its molar mass. In this case, the mass of KBr is given as 2.45 g. Then, divide the number of moles by the volume of the solution in liters (given as 2.30 L) to find the molarity.
8. To determine the number of moles of CaCl2 in the solution, you need to multiply its molarity by the volume of the solution in liters. In this case, the volume is given as 15.25 mL, but it needs to be converted to liters by dividing by 1000. Then, multiply the molarity (given as 2.10 M) by the volume in liters to find the number of moles.
9. The number of moles of KOH can be calculated by multiplying its molarity by the volume of the solution in liters (given as 64.3 mL). To convert the volume to liters, divide by 1000. Then, multiply the molarity (given as 0.0238 M) by the volume in liters to find the number of moles. To find the mass of KOH in grams, multiply the number of moles by its molar mass.
10. To find the volume of the KI stock solution needed to make the desired concentration, you can use the formula C1V1 = C2V2, which represents the dilution formula. In this case, the initial concentration (C1) is given as 3.00 M, the desired concentration (C2) is given as 1.25 M, and the desired volume (V2) is given as 0.300 L. Solve for V1, which would be the volume of the stock solution needed.
We do better with short posts. I'll help with the first. To do all of these takes too long for a single post.
What is the percent by mass of 3.55 g NaCl dissolved in 88 g H2O?
%by mass = g solute/100 g solution.
%NaCl = 3.55 g NaCl/(3.55g NaCl + 88 g H2O)*100 = ??