What is the value of x so that the perimeter of the triagle is at least 57?

14 on left side
x + 4 on right side
2x-3 on the bottom

Solve the following,

14 + x + 4 + 2x - 3 >= 57

12

x ≥ 14

To find the value of x that makes the perimeter of the triangle at least 57, we need to add up all the sides of the triangle and set the sum greater than or equal to 57.

The perimeter of a triangle is calculated by adding the lengths of all three sides together. In this case, the three sides are 14 (on the left side), x + 4 (on the right side), and 2x - 3 (on the bottom).

So, the equation to solve is:

14 + (x + 4) + (2x - 3) ≥ 57

To solve this equation, we will simplify and solve for x. Let's start by combining like terms:

14 + x + 4 + 2x - 3 ≥ 57

Combining like terms, we get:

3x + 15 ≥ 57

Next, we'll isolate the variable by subtracting 15 from both sides:

3x + 15 - 15 ≥ 57 - 15
3x ≥ 42

Finally, to solve for x, we'll divide both sides of the inequality by 3:

(3x)/3 ≥ 42/3
x ≥ 14

Therefore, the value of x that makes the perimeter of the triangle at least 57 is x ≥ 14.