The length of each piece in a model train railroad built on the HO scale is 1/87 of the actual length. Another popular model is the N scale, for which the scale is 1/160.
Each car on a full-size passenger train is 80ft long. What is the length in inches of a model passenger car in the HI scale? In the N scale?
HO gauge:
1/87 = x/80
Cross multiply and solve for x.
thank-you 4 the help
You're very welcome.
I am getting 0.9195in is this correct or should I round up or convert it to a fraction?
To find the length of a model passenger car in the HO scale, we can use the following steps:
1. Calculate the length of a model passenger car in the actual length scale:
Actual Length = Scale Factor * Model Length
Since the actual length of a passenger car is 80 ft, and the scale factor for the HO scale is 1/87, we can calculate:
Actual Length = (1/87) * 80 ft
2. Convert the actual length to inches:
Since there are 12 inches in 1 foot, we can convert the actual length from feet to inches:
Actual Length (in inches) = Actual Length (in feet) * 12
To find the length of a model passenger car in the N scale, we can use the same steps as above, but with the scale factor of 1/160.
Now let's calculate the lengths:
For the HO scale:
1. Actual Length = (1/87) * 80 ft = 0.9195 ft
2. Actual Length (in inches) = 0.9195 ft * 12 = 11.034 inches (approximately)
For the N scale:
1. Actual Length = (1/160) * 80 ft = 0.5 ft
2. Actual Length (in inches) = 0.5 ft * 12 = 6 inches
Therefore, the length of a model passenger car in the HO scale would be approximately 11.034 inches, and in the N scale, it would be 6 inches.