What would the function

H(x)=0.002x^2+0.005x-0.029 look like?

To visualize the function H(x) = 0.002x^2 + 0.005x - 0.029, you can plot it on a coordinate plane. Here's how you can do that:

1. Choose a range of values for x. For example, x can range from -10 to 10.

2. Plug in each x value into the equation to get the corresponding y value. For example, when x = -10, y = 0.002(-10)^2 + 0.005(-10) - 0.029, which you can evaluate to find the value of y.

3. Repeat this process for multiple x values within the chosen range. For example, you can calculate y for x = -9, -8, -7, ..., 8, 9.

4. Plot the points (x, y) on a coordinate plane. For each x value, locate the corresponding y value on the vertical axis and plot it. Connect the points with a smooth curve.

Once you have plotted enough points, you should see the shape of the graph. In this case, the function H(x) = 0.002x^2 + 0.005x - 0.029 is a quadratic function, which means it will have a parabolic shape. The specifics of the shape (e.g., the direction it opens, the location of the vertex) can be determined by analyzing the coefficients of the quadratic equation.

Note: If you are using a graphing calculator or a software program like Microsoft Excel or Google Sheets, you can input the equation directly and it will generate the graph for you.