What is the empirical formula of caffeine (C8 H10 N4 O2)?

How do I get it?
Thanks

You look for a number that divide into all of the subscripts evenly. For example, I see that all of the numbers can be divided evenly by 2. I would do that, then see if any other factor can be used. If not, then C4H5N2O will be the empirical formula.

IT GOOD ANS

To determine the empirical formula of caffeine (C8H10N4O2), you need to find the simplest ratio of the elements in the compound. Here's how to do it:

Step 1: Determine the molar mass of each element in the compound.
The molar mass for C (Carbon) is approximately 12.01 g/mol.
The molar mass for H (Hydrogen) is approximately 1.01 g/mol.
The molar mass for N (Nitrogen) is approximately 14.01 g/mol.
The molar mass for O (Oxygen) is approximately 16.00 g/mol.

Step 2: Multiply the number of atoms of each element by their respective molar masses.
C: 8 (atoms) * 12.01 (g/mol) = 96.08 g/mol
H: 10 (atoms) * 1.01 (g/mol) = 10.10 g/mol
N: 4 (atoms) * 14.01 (g/mol) = 56.04 g/mol
O: 2 (atoms) * 16.00 (g/mol) = 32.00 g/mol

Step 3: Calculate the molar mass of the empirical formula by summing up the molar masses of the elements.
96.08 g/mol + 10.10 g/mol + 56.04 g/mol + 32.00 g/mol = 194.22 g/mol

Step 4: Divide the molar mass of each element by the molar mass of the empirical formula to find the simplest ratio.
C: 96.08 g/mol / 194.22 g/mol ≈ 0.494
H: 10.10 g/mol / 194.22 g/mol ≈ 0.052
N: 56.04 g/mol / 194.22 g/mol ≈ 0.288
O: 32.00 g/mol / 194.22 g/mol ≈ 0.165

Step 5: Convert the ratios to the nearest whole number by dividing each ratio by the smallest ratio.
C: 0.494 / 0.052 ≈ 9.5 ≈ 10
H: 0.052 / 0.052 = 1
N: 0.288 / 0.052 ≈ 5.5 ≈ 6
O: 0.165 / 0.052 ≈ 3.2 ≈ 3

Step 6: Write the empirical formula using the whole numbers obtained.
The empirical formula of caffeine is C10H6N4O2.

Remember, the empirical formula represents the simplest whole-number ratio of atoms in a compound.

To determine the empirical formula of a compound, you need to know the relative number of atoms of each element present in the compound.

In the case of caffeine (C8H10N4O2), the given formula already provides the relative number of atoms for each element. The subscripts in the formula indicate the number of atoms of each element: 8 carbon (C) atoms, 10 hydrogen (H) atoms, 4 nitrogen (N) atoms, and 2 oxygen (O) atoms.

Therefore, the empirical formula of caffeine is C8H10N4O2. No further calculations are needed since the formula given represents the simplest whole number ratio of atoms in the compound.

In summary, to determine the empirical formula of a compound, you need to know the relative number of atoms of each element present. In this case, the given formula already provides that information, so no additional calculation is required.