a 3.11g sample of one of the halogens, Xsubscript2, is shown to react with NaOH to produce 2.00g NaX. the equation is 2NaOH+X subscript 2 yields NaX+NaXO+ water. Assuming that the percent yield of product is 100% identify the halogen.

To identify the halogen, we need to calculate the molar mass of Xsubscript2, the moles of NaX produced, and compare it to the molar masses of different halogens.

Let's break down the steps to find the answer:

1. Calculate the moles of NaX produced:
Molar mass of NaX = 2.00 g/mol
Moles = Mass / Molar mass
Moles of NaX = 2.00 g / 2.00 g/mol = 1.00 mol

2. Use the stoichiometric ratio from the balanced equation to find the moles of Xsubscript2:
According to the balanced equation: 2NaOH + Xsubscript2 -> NaX + NaXO + water
The ratio between NaX and Xsubscript2 is 1:1
Moles of Xsubscript2 = Moles of NaX = 1.00 mol

3. Calculate the molar mass of Xsubscript2:
Mass = Moles x Molar mass
Molar mass of Xsubscript2 = Mass / Moles
Molar mass of Xsubscript2 = 3.11 g / 1.00 mol = 3.11 g/mol

Now, we can compare the molar mass of Xsubscript2 (3.11 g/mol) with the known molar masses of halogens to identify which halogen it is.

Molar masses of halogens:
- Fluorine (F): 18.998 g/mol
- Chlorine (Cl): 35.453 g/mol
- Bromine (Br): 79.904 g/mol
- Iodine (I): 126.90 g/mol

Comparing the molar mass of Xsubscript2 (3.11 g/mol) to the molar masses of halogens, we find that it is closest to chlorine (Cl) with a molar mass of 35.453 g/mol.

Therefore, the halogen represented by Xsubscript2 is chlorine (Cl).