ok and i had another question:
convert the % elemental phosphorus(6.391%) to the % phosphorus present as phosphorous pentoxide (P2O5)
See you other post below.
You don't need but one post.
To convert the percentage of elemental phosphorus to the percentage of phosphorus present as phosphorous pentoxide (P2O5), you need to use the molar masses of both compounds.
1. Begin by calculating the molar mass of elemental phosphorus (P):
- The atomic mass of phosphorus (P) is approximately 30.97 grams/mol.
2. Next, calculate the molar mass of phosphorous pentoxide (P2O5):
- Phosphorous (P) has an atomic mass of approximately 30.97 grams/mol.
- Oxygen (O) has an atomic mass of approximately 16.00 grams/mol. Since there are five oxygen atoms in phosphorous pentoxide, multiply the atomic mass of oxygen by 5.
- The molar mass of phosphorous pentoxide (P2O5) is therefore calculated as:
(2 x 30.97) + (5 x 16.00) = 141.96 grams/mol.
3. Now, you can calculate the percentage of phosphorus present as phosphorous pentoxide (P2O5) using the following formula:
% phosphorus as P2O5 = (molar mass of P2O5 / molar mass of P) x % elemental phosphorus.
Substituting the values we calculated earlier:
% phosphorus as P2O5 = (141.96 / 30.97) x 6.391
Solve this equation to find the percentage of phosphorus present as phosphorous pentoxide (P2O5).
For example, if we solve the equation and get 29.30%, it means that 29.30% of the phosphorus in the compound is present as phosphorous pentoxide (P2O5).