How do you multipl (3a-2b)(4a+3b)??

(3a-2b)(4a+3b)

Using FOIL-first, outer, inner, last
(3a - 2b)(4a + 3b)
First = 3a * 4a = 12a^2
Outer = 3a * 3b = 9ab
Inner = -2b * 4a = -8ab
Last = -2b * 3b = -6b^2

12a^2 + 9ab - 8ab - 6b^2
Combine like terms
12a^2 + ab - 6b^2